-6+22w^2=-64w

Solution for -6+22w^2=-64w equation:

-6+22w^2=-64w

We move all terms to the left:

-6+22w^2-(-64w)=0

We get rid of parentheses

22w^2+64w-6=0

a = 22; b = 64; c = -6;
Δ = b2-4ac
Δ = 642-4·22·(-6)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-68}{2*22}=\frac{-132}{44}
=-3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+68}{2*22}=\frac{4}{44}
=1/11
$